The general solution of Wave Equation

Tags: #physics #general solution #waves

Equation

$$\frac{\partial^2 u(x,t)}{\partial t^2}=\sum_{m=0}^{N}\left(b_m\frac{\partial ^m}{\partial x^m}\right)u(x,t) \\ u(x,t)=\int\limits_{-\infty}^{\infty}\left(a(k){\rm e}^{i(kx-\omega_1(k)t)}+ b(k){\rm e}^{i(kx-\omega_2(k)t)}\right)dk \\ u(x,t)=A{\rm e}^{i(kx-\omega t)} \\ \omega_j=\omega_j(k)$$

Latex Code

                                 \frac{\partial^2 u(x,t)}{\partial t^2}=\sum_{m=0}^{N}\left(b_m\frac{\partial ^m}{\partial x^m}\right)u(x,t) \\ 
            u(x,t)=\int\limits_{-\infty}^{\infty}\left(a(k){\rm e}^{i(kx-\omega_1(k)t)}+ b(k){\rm e}^{i(kx-\omega_2(k)t)}\right)dk \\
            u(x,t)=A{\rm e}^{i(kx-\omega t)} \\
            \omega_j=\omega_j(k)
                            

Have Fun

Let's Vote for the Most Difficult Equation!

Introduction

Equation



Latex Code

            \frac{\partial^2 u(x,t)}{\partial t^2}=\sum_{m=0}^{N}\left(b_m\frac{\partial ^m}{\partial x^m}\right)u(x,t) \\ 
            u(x,t)=\int\limits_{-\infty}^{\infty}\left(a(k){\rm e}^{i(kx-\omega_1(k)t)}+ b(k){\rm e}^{i(kx-\omega_2(k)t)}\right)dk \\
            u(x,t)=A{\rm e}^{i(kx-\omega t)} \\
            \omega_j=\omega_j(k)
        

Explanation

The general solution of is given by above.


Related Documents

Related Videos

Discussion

Comment to Make Wishes Come True

Leave your wishes (e.g. Passing Exams) in the comments and earn as many upvotes as possible to make your wishes come true


  • Julie Wright
    Fingers crossed for passing this exam!
    2023-06-28 00:00

    Reply


    Joshua Moore reply to Julie Wright
    Gooood Luck, Man!
    2023-07-19 00:00:00.0

    Reply


  • Vincent Alexander
    Focusing all my positive energy on passing this exam.
    2023-07-27 00:00

    Reply


    Edna Bates reply to Vincent Alexander
    Gooood Luck, Man!
    2023-07-31 00:00:00.0

    Reply


  • Adam Bailey
    Getting a pass on this test would be a dream come true.
    2023-08-08 00:00

    Reply


    Margaret Thomas reply to Adam Bailey
    Nice~
    2023-09-03 00:00:00.0

    Reply